Lee washes the outsides of houses. It takes him 40 minutes to power wash a one-story home, and he uses 180 gallons of water. Power washing a two-story home takes less than 90 minutes, and he uses a maximum of 5,000 gallons of water per week. Lee works no more than 40 hours each week, and his truck holds 500 gallons of water. He charges $90 to wash a one-story home and $150 to wash a two-story home. Lee wants to maximize his weekly washing income washing houses. Let x represent the number of one-story houses and y represent the number of two-story houses. What are the constraints for the problem?

40x + 90y <2400

18x + 30y < 500

Step-by-step explanation:

Lee washes houses. It takes him 40 minutes to wash a one-story home, and he uses 18 gallons of water. Power washing a two-story home takes less than 90 minutes, and he uses 30 gallons of water. Lee works no more than 40 hours each week, and his truck holds 500 gallons of water. He charges $90 to wash a one-story home and $150 to wash a two-story home. Lee wants to maximize his income washing one- and two-story houses. Let x represent the number of one-story houses and y represent the number of two-story houses. What are the constraints for the problem

Let

x=one story houses

y=two story houses

The constraints are the following:

1. Lee works no more than 40 hours each week.

40 hours=40 × 60 minutes

=2400 minutes

2. Lee's truck holds 500 gallons of water.

it takes Lee 40 minutes and 18 gallons of water to wash a one-story house.

it takes Lee 90 minutes and 30 gallons of water to wash a two-story house.

First constraint:

40*x + 90*y < 2400

40x + 90y <2400

Second constraint:

18*x + 30*y < 500

18x + 30y < 500

.

step-by-step explanation:

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x