Given that El bisects ZCEA, which statements must be true? Select three options,

mZCEA = 90°

mZCEF = m ZCEA + m ZBEF

mZCEB = 2(m ZCEA)

ZCEF is a straight angle.

ZAEF is a right angle.

Question: Given that BE bisects ∠CEA, which statements must be true? Select THREE options.

(See attachment below for the figure)

m∠CEA = 90°

m∠CEF = m∠CEA + m∠BEF

m∠CEB = 2(m∠CEA)

∠CEF is a straight angle.

∠AEF is a right angle.

m∠CEA = 90°

∠CEF is a straight angle.

∠AEF is a right angle

Step-by-step explanation:

Line AE is perpendicular to line CF, which is a straight line. This creates two right angles, <CEA and <AEF.

Angle on a straight line = 180°. Therefore, m<CEA + m<AEF = m<CEF. Each right angle measures 90°.

Thus, the three statements that must be TRUE are:

m∠CEA = 90°

∠CEF is a straight angle.

∠AEF is a right angle

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1