Let T (x, y) = (x + 1, y + 1) and S (x, y) = (x + 5, y + 4). In what quadrant is S (T (P)) when P(-7, 1)?

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.

yes

step-by-step explanation:

they have to be opposite and reciprocal of eachother.