On a given day, a particular raccoon will eat the trash from one of three different houses. If he eats from the trash of a particular house, he has a 50% chance to eat from the same house the next day, and a 25% chance each to eat from one of the other two houses. What is the stochastic matrix for this scenario

Step-by-step explanation:

On a given day , a particular raccoon will eat the trash from one of three different houses.

Let assume be a random variable that illustrating  the house raccoon will eat on an unknown given nth day.

If he eats from the trash of a particular house, he has a 50% chance to eat from the same house the next day, and a 25% chance each to eat from one of the other two houses.

There are three states given in the above statement.

So, we can have state 1, state 2 and state 3

Assuming that:

state 1 = house 1

state 2 = house 2

state 3 = house 2

If he eats from the trash of a particular house,

For state 1 : he has a 50% chance to eat from the same house the next day

i.e state 1 = 0.50

and a 25% chance each to eat from one of the other two houses.

For state 2 and state 3: = 0.25

i.e state 2 = 0.25

state 3 = 0.25

NOW:

The stochastic matrix for this scenario can be computed as:

                  0          1       2

70,000 + 6,000 + 800 + 30

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;