AC = 22, BC = x + 14, and AB = x + 10.
Find x.

Hi there! :)

Given:

AC = 22

BC = x + 14

AB + x + 10

AC is equivalent to AB + BC, therefore:

AC = AB + BC

Substitute in the expressions:

22 = (x + 10) + (x + 14)

Combine like terms:

22 = 2x + 24

Subtract 24 from both sides:

-2 = 2x

Divide both sides by 2:

x = -1

Given : AC = 22, BC = x + 14, and AB = x + 10.

Solution :

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