Plz answer it, plz answer it, plz answer it.

Given that :-

To Find :-

Solution :-

The fist expression x + y < 5 states that sum of x and y could be any rational number less than 5 .

And the second expression 3 < x < 5 states that value of x could be any rational number between 3 and 5.

Let's check which option suits best.

Is it possible to have value of 8/3 by y ?

→ x + 8/3 < 5

→ x < 5 - 8/3

→ x = 7/3

7/3 is a rational number . So y as 8/3 is possible value.

→ 7/3 = 2.33

But value of x should be greater than 3 .

So option A is wrong.

Is it possible to have value 2 by y ?

→ x +2 < 5

→ x < 5-2

→ x < 3 .

But value of X should be greater than 3.

So option B is also incorrect.

Is it possible to have value 0 by y?

→ x +0 <5

→ x < 5

It also fullfill 2nd expression that X should have value less than 5 and greater than 3.

So option C is valid .

Value of y is 0 .

can i see the following ?

step-by-step explanation:

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.