If $-3\le x+5 \le 8$ and $x$ is an integer, what is the sum of all the possible solutions?

-30

Step-by-step explanation:

The integers are the whole numbers and the opposite of the whole numbers.

That is {...,-3,-2,-1,0,1,2,3,...} is the set of integers.

If it is a number you count with or the opposite of a number you count with it or 0, then it is an integer.

So we need to solve the inequality first, and then just say all the integers included in that compound inequality. Last step is to add since it is asking for the sum of those integers.

Let's do this.

Subtract 5 on all sides:

Simplify all sides:

This inequality includes all numbers between -8 and 3, and both include -8 and 3 because of the equal part on both of the inequality parts.

So we have -8,-7,-6,-5,-4,-3,-2,-1,0,1,2, and 3 are the integer solutions of this inequality.

Let's add them. I'm going to put opposites together because I know they will zero out.

So I have this:

-8+-7+-6+-5+-4+-3+-2+-1+0+1+2+3

-8+-7+-6+-5+-4+(-3+3)+(-2+2)+(-1+1)+0

-8+-7+-6+-5+-4+0       +0        +0     +0

-8+-7+-6+-5+-4

-(8+7+6+5+4)

-([8+7]+[6+5]+4)

-([15]+[11]+4)

-(15+11+4)

-([15+11]+4)

-([26]+4)

-(26+4)

-(30)

-30

the answer is c hope it

step-by-step explanation: