The perimeter of a rectangle is 38 units. The length is 13 units longer than the width. What are the dimensions of the rectangle? A 18 by 5
B. 12 by 7
Oc is by a
0.16 by

D (Presumably)

16 by 3

Step-by-step explanation:

The perimeter of a rectangle is the two lengths added with the two widths. In a formula, this is:

Where l is the length and w is the width.

We are told the length is 13 units longer than the width. In other words:

We also already know that the perimeter is 38 units. So, let's substitute P for 38 and l for (w+13) to solve for w:

Distribute:

Combine like terms:

Subtract 26 from both sides:

Divide both sides by 4:

Thus, the width is 3 units.

Since the length is 13 units longer than the width, the length is 16 units.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

other answer is correct. i had used the radius of the radius somehow. a website: