In a certain Algebra 2 class of 21 students, 11 of them play basketball and 6 of them play baseball. There are 6 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?

Step-by-step explanation:

total number of students=21

students play neither sport=6

students who play at least one sport=21-6=15

Let play basketball=X

and play baseball=Y

n(XUY)=n(X)+n(Y)-n(X∩Y)

15=11+6-n(X∩Y)

n(X∩Y)=17-15=2

reqd. probability=2/21

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

i think the answer is fried chicken ; >

step-by-step explanation: