Find HCF of 96 and 404 by prime factorization method and find their LCM

HCF of 96 and 404 by prime factorisation method:-

Since, 96 = 2 × 2 × 2 × 2 × 2 × 3

and, 404 = 2 × 2 × 101

So, HCF of 96 and 404 = Product of common prime factors

                                 = 2 × 2 = 4

LCM = 2 × 2 × 2 × 2 × 2 × 101 × 3

       = 9696

Step-by-step explanation:

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step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)  

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1