You travel from City X to City Y. You know that the round-trip distance is 647 miles. City Z, a city you pass on the way, is 27 miles from City X. Find the distance from City Z to City Y. The distance from City Z to City Y is miles.

296.5 miles

Step-by-step explanation:

Round trip distance of City X to City Y is 647 miles.

Round trip includes to and fro.

i.e. City X to City Y and then City Y to City X back.

Let the distance between City X and City Y = D

Distance traveled in round trip between City X and City Y = D + D = 2D

Given than 2D = 647

OR

D = = 323.5 miles

Kindly refer to the attached diagram, for the location of City Z.

Distance between XY = Distance from X to Z + Distance from Z to Y.

Distance XY = XZ +ZY

323.5 = 27 +ZY

ZY =296.5 miles

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

dude thats to long figure it

step-by-step explanation: