A church spire casts a shadow on the level ground. At the tip of the shadow, the tip of the spire lies 25° upward. Walking 100 m closer, the tip of the spire is at an angle of 55°. What must be the height of the spire in Figure 2?

The height of the spire must be 69.24 m

Step-by-step explanation:

The information given are;

The initial angle of elevation of the tip of the spire from the tip of the shadow = 25°

The  angle of elevation of the tip of the spire from the tip of the shadow after moving 100 m closer = 55°

The change distance moved closer to the church spire = 100 m

Let the base angles of the triangle formed by the two rays of the tip of the spire to the tip of the shadow be 25° and ∠x°

We have;

∠x° and the 55° angle of the ray from the tip of the spire to the tip of the shadow are supplementary angles (angle on a straight line)

Therefore;

∠x° = 180° - 55° = 125°

The calculated angle 125° above, the given 25° and the angle in between the two rays from the tip of the spire to the tip of the shadows are the interior angles of the triangle formed by the two rays of the tip of the spire to the tip of the shadow

Let the angle in between the two rays from the tip of the spire to the tip of the shadows = y

Therefore;

125° + y° + 25° = 180 (Angle sum theorem)

y° = 180° - (125° + 25°) = 30°

By sin rule, we have;

100/(sin (30°)) = (The length of the initial ray from the tip of the spire to the tip of the shadow before the shift)/(sin(125°))

Let the length of the initial ray from the tip of the spire to the tip of the shadow before the shift = l

100/(sin (30°)) = l/(sin(125°))

l = (sin(125°))×100/(sin (30°)) = 163.83 m

The height of the spire, by trigonometric ratio = sin(25°) × 163.83 m = 69.24 m

The height of the spire = 69.24 m.