Does anyone know how to solve this? I tried moving the 3 back to make it log 2 (x^3) but for the second one it would be (5x)^2 and I get stuck there

x = 100

Step-by-step explanation:

All you need is contained in the sheet attached

x = 100

Step-by-step explanation:

3 log2(x) - 2 log2(5x) = 2

We know that a log(c) = log c^a

log2(x)^3 - log2(5x)^2 = 2

log2(x^3) - log2(25x^2) = 2

We know that log a - log b = log a/b

log2(x^3 /25x^2) = 2

Simplify

log2(x /25) = 2

Raise each side to  base 2

2^log2(x /25) = 2^2

x/25 = 4

Multiply each side by 25

x = 4*25

x = 100

answer: t=3

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt