In the class of 40 students,18 passed mathematics,19 passed account,16 passed economics,5 passed mathematics and accounts only ,2 passed accounts and economics only. if each student offered at least one of the subject a: how many students failed in all the subjects
b: find the percentage number who failed in at least one of economics and mathematics
C: calculate the probability that a student selected at random failed in accounts..

A) 4 students

B) 32.5%

C) 19/40

Step-by-step explanation:

Using set notation to solve the problem with universal set n(U) = 40

Let n(A) be the number of students that pass account

n(E) be the number of students that pass economics

n(M) be the number of students that pass mathematics

n(AUEUM)' be number of students that failed in all the 3 subjects.

n(AUEUM) be number of students that pass in all the 3 subjects.

n(U) = n(AUEUM)+ n(AUEUM)'

Find the remaining solution in the attachment

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation:

180-142=38 for the acute angle next to the entry

90+38=128

180-128=52

a=52

step-by-step explanation: