A company is replacing cables with fiber optic lines in rectangular casing BCDE. If segment DE = 2.5 cm and segment BE = 3 cm, what is the smallest diameter of pipe that will fit the fiber optic line? Round your answer to the nearest hundredth. 3.54 cm 3.91 cm 4.24 cm 4.95 cm

BD would be the hypotenuse of a right triangle, which would also be the diameter of the pipe.

Use the Pythagorean theorem:

BD = sqrt(2.5^2 + 3^2)

BD = sqrt(6.25 + 9)

BD = sqrt(15.25)

BD = 3.91 cm

Step-by-step explanation:

The triangle BDE is a right triangle.

Line segment DE = 2.5 cm

Line segment BE = 3 cm

We can apply Pythagorean theorem to solve for the diameter of the pipe or the hypotenuse of the right triangle BDE.

We can round up the length to nearest hundredth.

The diameter of the pipe is 3.91 cm.

46.2+112.3

step-by-step explanation: