I need step by step explanation for this problem :) Thank you >3

Step-by-step explanation:

Since Bridget rows 1 hour 4 kilometers upstream and 30 minutes (half of one hour) kilometers, downstream, then we have to find the average speed of both times. First, let's find how long Bridget would have to row upstream every kilometer.

Step 1:

60 minutes ÷ 4 kilometers = 15 minutes per kilometer (upstream)

30 minutes ÷ 4 kilometers = 7.5 minutes per kilometer (downstream)

Step 2:

Now, we find the average of 15 and 7.5. To do that, we add the values together and divide them by the number of values there are (2).

15 + 7.5 = 22.5

22.5 ÷ 2 = 11.25

Bridget takes 11.25 minutes to row 1 kilometer in still water.

Bridget rows at an average of 6 km per hour. The speed of the current is 2 km per hour.

Step-by-step explanation: Given the distance of 4 km and the two times, 1 hr and 1/2 hr, we can figure the speeds to be 4k/h and 8k/h. The average is 6k/h. The difference between her average and the actual speeds recorded is 2k/h against hr going upstream and with her going downstream.

3x + 18 = 147°

step-by-step explanation:

3x + 18 = 147°, because the value of the central angle is equal to the value of the arc formed by it.

i hope i you.

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!