-4.75 = x/2 what is x

x= -9.5

Step-by-step explanation:

We want to find out what the variable, x, is equal to. Therefore, we must isolate the variable on one side of the equation.

-4.75 = x/2

x is being divided by 2. The inverse of division is multiplication. Multiply both sides of the equation by 2.

2*(-4.75) = (x/2)*2

2*(-4.75)=x

2* -4.75=x

Multiply 2 and -4.75

-9.5=x

Let's check our solution. Plug -9.5 back in for x and solve.

-4.75= x/2

-4.75= -9.5/2

-4.75= -4.75

This checks out, so we know our solution is correct.

x is equal to -9.5

Step-by-step explanation:

First convert the decimal to an improper fraction

That's

So we have

Cross multiply

4x = - 38

Divide both sides by 4

We have the final answer as

Hope this helps you

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.