HII PLEASE HELP ME IN THIS

Step-by-step explanation:

(i) Sum the forces at point M in the x direction.

∑F = ma

-T sin 30° − T sin 30° + 5 N = 0

2T sin 30° = 5 N

T = 5 N

(ii) Sum the forces on the ring in the x direction.

∑F = ma

T sin 30° − N = 0

N = 2.5 N

Sum the forces on the ring in the y direction.

∑F = ma

T cos 30° − mg − Nμ = 0

Nμ = T cos 30° − mg

2.5 μ = 5 cos 30° − 2

μ = 0.932

(iii) Sum the forces on the ring in the y direction.

∑F = ma

T cos 30° − m₁g − m₂g + Nμ = 0

m₂g = T cos 30° − m₁g + Nμ

m (10) = 5 cos 30° − 2 + (2.5)(0.932)

m = 0.466 kg