It is known that 60% of customers will need additional maintenance on their vehicle when coming in for an oil change. A random sample of 48 customers is taken. What is the probability that more than 70% of customers in the sample will need additional maintenance

the probability that more than 70% of customers in the sample will need additional maintenance is 0.0371

Step-by-step explanation:

From the information given:

we are to determine the probability that more than 70% of customers in the sample will need additional maintenance

In order to achieve that, let X be the random variable that follows a binomial distribution.

Then X Bin(48, 0.6)

However 70% of 48 samples is

= 0.7 × 48 = 33.6 34

Therefore, the required probability is:

= P(X> 34)

= 0.03709524328

0.0371

don't report but were is the digram

step-by-step explanation: