An electronic product takes an average of 4 hours to move through an assembly line. If the standard deviation is 0.5 hours, what is the probability that an item will take between 2.8 and 4.3 hours to move through the assembly line

0.7176

Step-by-step explanation:

We solve this question, using z score formula.

Z score formula = (x - μ)/σ

where x is the raw score

μ is the population mean

σ is the population standard deviation.

For z1, where x1 = 2.8, μ = 4, σ = 0.5

z score formula = (2.8 - 4)/0.5

= -2.4

We find the probability of the z score using the z score table.

P(x = 2.8) = P(z = -2.4)

= 0.0081975

For z2, where x2 = 4.3, μ = 4, σ = 0.5

z score formula = (4.3 - 4)/0.5

= 0.3/0.5

= 0.6

We find the probability of the z score using the z score table.

P(x = 4.3) = P(z = 0.6)

= 0.72575

The probability that an item will take between 2.8 and 4.3 hours to move through the assembly line is calculated as:

= 2.8 < x < 4.3

= P(z = 0.6) - P(z = -2.4)

= 0.72575 - 0.0081975

= 0.7175525

Approximately ≈ 0.7176

Therefore, the probability that an item will take between 2.8 and 4.3 hours to move through the assembly line is 0.7176

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (