an experiment consists of rolling two fair dice and adding the dots on the two sides facing up assuming each simple event is as likely as any other find the probability that the sum of the dots is greater than 2

35/36

Step-by-step explanation:

Sample space = S

n(S) = 36

Event of obtaining sum greater than 2, = A

Event of obtaining sum less than 2, B =( 1, 1)

n(B) = 1  

Probability of obtaining sum less than 2, P(B) = n(B)/n(S) = 1/36

n(A) = 36 - 1 = 35

∴ Probability of obtaining sum greater than 2, P(A) = n(A)/n(S) = 35/36

.

step-by-step explanation:

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;