A ball is thrown vertically upward. After t seconds, its height h, in feet, is given by the function LaTeX: h\left(t\right)=-16t^2+64th ( t ) = − 16 t 2 + 64 t. How many seconds will it take the ball to reach its maximum height?

The time it will take for the ball to reach maximum height of 64 feet is 2 seconds

Step-by-step explanation:

The given equation for the height, h, in feet the ball reaches is given by the function;

h(t) = -16·t² + 64·t

To reach maximum height, , we have;

At , we have;

Which gives;

64 -32·t = 0

64 = 32·t

t = 64/32 = 2 seconds

Therefore, it will take 2 seconds for the ball to reach maximum height

The maximum height reached is given as follows;

h(2) = -16×2² + 64×2 = 64 feet

The time it will take for the ball to reach maximum height of 64 feet is 2 seconds.

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d≈7.07in

step-by-step explanation: