One of the digits of a two digit number is three times the other digit. If you interchange the digits of this two digit number and add the resulting number to the original number you get 88 . Find the original number

62

Step-by-step explanation:

well, we start by expressing the number:

a b

we understand that using the above expression, the value of the number is 10a + b

using the information in the question,

a = 3b (1)

and,

11b + 11a = 88 (2) (derived using 10a + b form)

hence, when substituting (1) into (2):

11b + 33b = 88

44b = 88

b = 2 (3)

sub (3) into (1)

a = 6

hence, the number is 62

f

step-by-step explanation:

f