What is the equation of the line?A. y=3/4x−1 B. y=4/3x+1 C. y=3/4x+1 D. y=4/3x−1

  B.  y = 4/3x + 1

Step-by-step explanation:

The offered choices are in slope-intercept form:

  y = mx + b

where m represents the slope (rise/run) and b represents the y-intercept.

The graph crosses the y-axis at y=1, so the y-intercept is +1. That eliminates choices A and D.

The slope is greater than 1, so choice C is eliminated. You know the slope is greater than 1 because the line goes up more than 1 unit for a 1-unit change to the right. If you look where the line crosses grid points, you see that it rises 4 units for a run of 3 units to the right. That means ...

  m = rise/run = 4/3

The equation is ...

  y = 4/3x +1 . . . . matches choice B

B. y = 4/3x + 1

Step-by-step explanation:

First, find the slope using rise/run (y2 - y1) / (x2 - x1)

Use the points (0, 1) and (3, 5)

Plug in the numbers:

(5 - 1) / (3 - 0)

= 4/3

Looking at the graph, we can see the y intercept is (0, 1) so we can plug in 1 into the equation y = mx + b as b:

y = mx + b

y = 4/3x + 1

exactly you go it

step-by-step explanation:

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !