Mathematics, 13.08.2020 22:01 jamiezanfardino1464
Given: AB ∥ DE Prove: △ACB ~ △DCE Triangle A B C is shown. Line D E is drawn inside of the triangle and is parallel to side A B. The line forms triangle D C E. We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA. We can state ∠C ≅ ∠C using the reflexive property. Therefore, △ACB ~ △DCE by the AA similarity theorem. SSS similarity theorem. AAS similarity theorem. ASA similarity theorem.
Answers: 3
Mathematics, 21.06.2019 16:20
Giuseppi's pizza had orders for $931.00 of pizzas. the prices were $21 for a large pizza, 514 for a medium pizza, and $7 for a small pizza. the number of large pizzas was two less than four times the number of medium pizzas. thenumber of small pizzas was three more than three times the number of medium pizzas. how many of each size of pizza were ordered?
Answers: 1
Mathematics, 21.06.2019 22:00
1. how do you convert the repeating, nonterminating decimal 0. to a fraction? explain the process as you solve the problem.
Answers: 2
Given: AB ∥ DE Prove: △ACB ~ △DCE Triangle A B C is shown. Line D E is drawn inside of the triangle...
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