Gerald graphs the function f(x) = (x – 3)2 – 1. Which statements are true about the graph? Select three options.

The answer is "Choice B, C, and F is correct".

Step-by-step explanation:

The following are choices, which is missing in the question, that can be defined as follows:

A) {x| x ≥ 3} is the domain.  

B) The set shall be {y| y ≥ –1}.  

C) over the interval  (–∞, 3), is the function, that decreases.  

D) it's over the duration the function increases its value, that is (–1, ∞).  

E) The symmetry axis will be x = – 1.  

F) vertex is (3, – 1).

In choice A, It is incorrect even though f is the domain, which is all true numbers because it has a quadrant function.  In choice B, it is correct.  In choice C, It is valid because it was a parable open with vertex so if we exploded view f (3, -1). Because as value opens up, its value with x from-∞ to 3 drops while it goes up from increasing from 3 to ∞.    In choice D, It is wrong since we have just said f decreases from-∞ to 3. Therefore, f decreases from -1 to 3, too. Therefore, f doesn't grow from -1 to ∞.  In choice E, It is incorrect because the symmetry axis is x = 3.  In choice F, it is true.