A ball is thrown straight up, from 3 m above the ground, with a velocity of 14 m/s. The equation to model this path is h(t)= -5t^2 + 14t + 3. How
would you find when the ball is 8 m above the ground?
Your answer
O This is a required question
If you can, find the solution to the above problem and briefly describe
how you found your solution.
Your answer

probably the 2.38 seconds answer

Step-by-step explanation:

start by setting the entire equation equal to 8, since h(t) is the height and 8m is the height we are looking at right now.

subtract 8 from both sides to get:

use the Quadratic equation to find the time, the negative answer does not count.

when you do the quadratic equation you get

In decimal form that's about  2.38 and 0.42 You'd probably go with the 2.38 seconds because the ball starts at 0 seconds, so the lower number is probably to close to the start point.

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

step-by-step explanation:

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