ILL GIVE BRAINLIEST HELP Two planes have a cruising speed of 750 km/h without wind. The first plane flies for 13 hours against a constant headwind. The second plane flies for 11 hours in the opposite direction with the same wind (a tailwind). The second plane flies for 250 km less than the first plane. Determine two equations that could be used to solve for the wind speed, w, and the distance traveled by the first plane, d.

1. (750+w)(13)=d (750+w)(11)=d+250 2. (750−w)(13)=d (750+w)(11)=d−250 3. (750+w)(13)=d (750−w)(11)=d−250 4. (750−w)(13)=d (750−w)(11)=d+250

The correct option is;

2. (750 - w)(13) = d (750 + w)(11) = d - 250

Step-by-step explanation:

The items with information given are;

The cruising speed of the planes = 750 km/h

The first plane flies against a constant headwind = w

The second plane flies against a constant tailwind  in magnitude to the headwind

The time duration of flight of the first plane = 13 hours

The time duration of flight of the second plane = 11 hours

The distance flown by the second plane = The distance flown by the first plane - 250 km

When we take the headwind magnitude as, w and the distance flown by the first plane as d, we have;

Speed of flight of the first plane = 750 - w

Speed of flight of the second plane = 750 + w

Therefore, the distance flown by the first plane in 13 hours is given as follows;

(750 - w) × (13) = d

Then we have;

The distance flown by the second plane in 11 hours is (750 + w) × (11) = d.

The correct option is (750 - w)(13) = d, (750 + w)(11) = d - 250

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step-by-step explanation: