Is the given equation a quadratic equation? Explain. x(x−6)=−5 The equation is not a quadratic equation because there is no x2-term.

The equation is a quadratic equation because there is an x2-term.

The equation is not a quadratic equation because the expression is not equal to zero.

The equation is not a quadratic equation because there is a term with degree higher than 2.

I think the answer is A but im not sure.

Your required answer is option A.

Step-by-step explanation:

Here,

The given equation is;

x(x-6)=-5

now,

while finding x.

eitheror,

x=-5(x-6)=-5

x= 1(shifting-6 in next side)

now, the value of x is -5,1.

so, it's a quadratic equation.

( in quadratic equation the variable always has two values after solution)

Hope it helps..

The equation is a quadratic equation because there is an x2-term.

Step-by-step explanation:

x(x−6)=−5

Distribute

x^2 -6x = -5

The equation is a quadratic equation because there is an x^2-term.

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c