The polynomial P(x) = 5x2(x − 1)3(x + 9) has degree It has zeros 0, 1, and The zero 0 has multiplicity , and the zero 1 has multiplicity

The complete question is;

The polynomial P(x) = 5x²(x − 1)³(x + 9) has degree . It has zeros 0, 1, and . The zero 0 has multiplicity , and the zero 1 has multiplicity

A) degree = 6

B) -9 is also a zero of the polynomial

C) 0 has multiplicity of 2

1 has multiplicity of 3

Step-by-step explanation:

A) To find the degree of the polynomial, we will first have to identify each term [term is for example (x - 1)³]. Thus, to find the degree of each term we will add the exponents.

The terms are;

5x², (x - 1)³, (x + 9)

The exponents are, 2, 3 and 1 respectively.

Thus, degree = 2 + 3 + 1 = 6

B) A zero of a polynomial is the value of x that causes the polynomial function to equal 0.

Since 0 and 1 are zeros, looking at the polynomial P(x) = 5x²(x − 1)³(x + 9), we can tell that when the term which when x = 0 makes the polynomial 0 is 5x².

Similarly, the term which when x = 1 makes the polynomial 0 is (x - 1)³

Thus,we are left with the term (x + 9)

So for the polynomial to be zero, (x + 9) = 0

Thus,x = -9

So -9 is a zero of the polynomial

C) The zero 0 is from the term 5x².

Thus,the multiplicity is the highest power of x which is 2.

The zero 1 is from the term (x - 1)³. Thus, the multiplicity is the highest power of x which is 3

answer: what are the following choices