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Mathematics, 12.08.2020 08:01 meganm9889

Given the following three points, find by hand the quadratic function they represent. (0,6), (2,16), (3, 33)
(1 point)
f(x) = 4x2 – 3x + 6
f(x) = -4x2 – 3x + 6
Of(x) = -4x2 + 21x + 6
Of(x) = 4x2 + 3x + 6

Given the following three points, find by hand the quadratic function they represent.
(-1,-8), (0, -1),(1,2)
(1 point)
O f(x) = -3x2 + 4x - 1
O f(x) = -2x2 + 5x - 1
Of(x) = -5x2 + 8x - 1
O f(x) = -3x2 + 10x - 1

Find the equation of a parabola that has a vertex
(3,5) and passes through the point
(1,13). (1 point)
Oy=2(x – 3)' + 5
Oy= -2(x – 3)' + 5
Oy= -3(x – 3)' +5
Oy= 2(x + 3)" - 5

Determine if the following set of ordered pairs represents a quadratic function. Explain.
(5, 7), (7, 11), (9, 14), (11, 18)
(1 point)
The y-values go up by the square of the x-value (22 = 4). Therefore, the ordered pairs represent a quadratic equation.
The y-values go up by the square of the x-value (22 = 4). Therefore, the ordered pairs do not represent a quadratic equation.
Since the differences between the differences of the y-values is not consistent, the ordered pairs do not represent a quadratic equation.
Since the differences between the x-values is 2 and the differences between the y-values is 4, that means that the differences between the differences
of the y-values are all zero. Therefore, the ordered pairs represent a quadratic equation.

Determine if the following table represents a quadratic function. Explain.
Ρ…
1
2
3
4.
5
y 13 22 37 58 85
(1 point)
O The differences between the differences of the y-values is a constant 6, so the ordered pairs do not represent a quadratic equation.
The differences between the y-values is a constant 9, so the ordered pairs represent a quadratic equation.
The differences between the differences of the y-values is a constant 6, so the ordered pairs represelo a quadratic equation.
The differences between the y-values is a constant 9, so the ordered pairs do not represent a quadratic equation.

i’m in a rush :( pls help

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