Following are the outcomes that are possible when a couple has three children. Refer to that list, and find the probability of each event. 1st 2nd 3rd
Boy Boy Boy
Boy Boy Girl
Boy Girl Boy
Boy Girl Girl
Girl Boy Boy
Girl Boy Girl
Girl Girl Boy
Girl Girl Girl
a. Among three children, there are exactly 2 boys.
b. Among three children, there are exactly o girls.
c. Among three children, there is exactly 1 girl.
1. What is the probability of exactly 2 boys out of three children?
2. What is the probability of exactly 0 girls out of three children?
3. What is the probability of exactly 1 girl out of three children?

a.0.375

b.0.125

c.0.375

1.0.375

2.0.125

3.0.375

Step-by-step explanation:

a.

The total events in a sample space are n(S)=8

The events that contains exactly two boys

Boy Boy Girl,Boy Girl Boy,Girl Boy Boy.

Let A be the event that there are exactly two boys. Thus, n(A)=3.

So, probability of exactly 2 boys is P(A)=n(A)/n(S)=3/8=0.375.

b.

The event that contains exactly 0 girls.

Boy Boy Boy

Let B be the event that contains exactly 0 girls. Thus, n(B)=1.

So, probability of exactly 0 girls is

P(B)=n(B)/n(S)=1/8=0.125.

c.

The events that contains exactly 1 girl.

Boy Boy Girl,Boy Girl Boy,Girl Boy Boy

Let C be the event that contains exactly 1 girl. Thus, n(C)=3.

So, probability of exactly 1 girl is

P(C)=n(C)/n(S)=3/8=0.375.

Q1 is same as part a.

Q2 is same as part b.

Q3. is same as part c

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.

your answer is

a.

5

step-by-step explanation: