Use the frequency distribution, which shows the number of American voters (in millions) according to age, to find the probability that a voter chosen at random is in the 18 to 20 years old age range

Ages

18 to 20

21 to 24

25 to 34

35 to 44

45 to 64

65 and over

Frequency

4.2

7.8

20.8

23.7

50.1

28 2

Date

07/2

3:29

The probability that a voter chosen at random is in the 18 to 20 years old age range is 0.0311

(Round to three decimal places as needed.)

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8:52

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2:42

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07/1

12:00

The probability that a voter chosen at random is in the 18 to 20 years old age range is =  4.2/ 134.8= 0.0311572

Step-by-step explanation:

We can find the probability by simply dividing the frequency of the ages range of 18-20 by the total frequency.

Ages                Frequency

18 to 20             4.2

21 to 24             7.8

25 to 34           20.8

35 to 44           23.7

45 to 64           50.1

65 and over       28.2

∑                        134.8

The probability of an event is given by the occurrence of an event by the total occurrences .

So

Here the occurrence of ages 18-20 is given by 4.2

and the total frequency is 134.8

The probability that a voter chosen at random is in the 18 to 20 years old age range is =  4.2/ 134.8= 0.0311572

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.