Find the perimeter of the following shape, rounded to the nearest tenth:

B, 19.1

Step-by-step explanation:

Imagine that each side is the hypotenuse of a triangle. You want to use the Pythagorean theorem on each of these triangles to find the length of the side.

Let's start with AB:

One side of the triangle is the distance between the points in the x direction only. A is at the x-coordinate of -3 while B is at the x-coordinate of 2. The side is, thus, 5 units.

The other side of the triangle is the distance between the points in the y direction only. A is at the y-coordinate of 5, while B is at 6. The distance is 1 unit.

So we have a triangle with the base of 5 and the height of 1. The Pythagorean theorem says:

Base² + Height² = Hypotenuse²

Or

a² + b² = c²

where a, b are the sides, and c is the hypotenuse.

Put our values into this, the base is 5 and the height is 1:

5² + 1² = c²

25 + 1 = 26 = c²

c = √26 ≈ 5.1

Repeat this for the lengths BC, CD, and DA.

BC

x-difference = 2

y-difference = 4

4² + 2² = c²

20 = c²

c = √20 ≈ 4.47

CD

x-difference = 5

y-difference = 1

(since this is the same as AB we can use that value ≈ 5.1 )

DA

x-difference = 2

y-difference = 4

(since this is the same as BC, we can use that value ≈ 4.47)

Add all these together:

5.1 + 5.1 + 4.47 + 4.47 ≈ 19.14

(Note: this is not exact, but it's good enough for this purpose)

The closest option to this is B, 19.1 - thus, B is the answer.

it’s the first one your welcome

can you put the picture up?

step-by-step explanation: