Can someone please help me with this problem?? **It's high-school geometry.

Hello!

To solve, we will need to use Right-Triangle Trigonometry:

Begin by solving for angles ∠S and ∠R using tangent (tan = opp/adj)

tan ∠S = a / (1/2b)

tan ∠S = 3√5 / 14

tan ∠S ≈ 0.479

arctan 0.479  = m∠S (inverse)

m∠S and m∠R ≈ 25.6°

Use cosine to solve for the hypotenuse, or the missing side-length:

cos ∠S = 14 / x

x · cos (25.6) = 14

x  = 14 / cos(25.6)

x ≈ 15.52

Both triangles are congruent, so we can go ahead and find the perimeter of the figure:

RS + RQ + QS = 28 + 15.52 + 15.52 = 59.04 units.

Hope this helped you! :)

Step-by-step explanation:

Take one small triangle, solve for hypotenuse.

Use Pythagorean theorem.

Add the hypotenuse twice because there are two triangles, then add to the length of b to find the perimeter.

4 packs of water and 7 packs of candy bars

step-by-step explanation:

35x4=140

140/20=7

3; 9 is 8 to -4

step-by-step explanation: