Find the largest number apart from 840 that is a multiple of 24 and a factor of 840.

168

Step-by-step explanation:

first, split both 840 and 24 into there primes.

840=2×2×2×3×5×7

24=2×2×2×3

therefore any multiples of 24 must have those factor.

so, factors of 840 that are multiples of 24 are

2×2×2×3=24

2×2×2×3×5=120

2×2×2×3×7=168

2×2×2×3×5×7=840

there the answer is 168

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

correct

step-by-step explanation: