Which of the following equations have infinitely many solutions? Choose all answers that apply:

A10x- 10 = -10x + 10
B- 10x - 10 = -10x + 10
C-10x – 10 = -10x - 10
D10x - 10 = -10x – 10

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An equation with infinite solutions has a solution of x=x. You can plug in any x-value and it will equal x, so there are infinitely many solutions.

ANSWER A

10x-10=-10x+10

We add 10 to both sides.

10x=-10x+20

We add 10x to both sides.

20x=20

We divide both sides by 20.

x=1

We have a solution of 1, so this is not an equation with infinitely many solutions.

Answer B

-10x-10=-10x+10

We add 10 to both sides.

-10x=-10x+20

We add 10 x to both sides.

0=20

This has no solutions because the x is gone, so there cannot be a solution.

Answer C

-10x-10=-10x-10

We add 10 to both sides.

-10x=-10x

We divide both sides by -10.

x=x

This has infinitely many solutions.

Answer D

10x-10= -10x-10

We add 10x to both sides.

20x-10=-10

We add 20 to both sides.

20x=0

We divide both sides by 20.

x=0

There is a single solution here, not infinitely many.

Therefore, the answer is C. -10x-10=-10x-10.

Have a wonderful day! :D

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.