Which function has only one x-intercept at (-6, 0)? Of(x) = x(x-6)
O f(x) = (x - 6)(x - 6)
f(x) = (x + 6)(x - 6)
Of(x) = (x + 6)(x + 6)

D.  f(x) = (x+6)(x+6)

Set (x+6)(x+6) equal to zero and solve each equation for x. We really only have one equation and it would be x+6 = 0 which solves to x = -6.

Plug x = -6 into f(x) and you would get f(x) = 0.

Ais c multiple rthvjjbv

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*