The test scores of students in a math class are 46, 40, 50, 43, 35, 41, 50, 42, 38, and 48. What is the mean of this set of data? A. 35.6 B. 40 C. 43.3 D. 50

C. 43.3

Step-by-step explanation:

The mean or average of a data set can be found by adding up all the values and dividing by the number of values.

1. Add up all the values

The values:  46, 40, 50, 43, 35, 41, 50, 42, 38, 48

Add them together:  46 +40+50+ 43+35+41+50+ 42+38+48

433

2. Divide by the number of values

Count how many numbers are in the set of data.

Data Set: 46, 40, 50, 43, 35, 41, 50, 42, 38, 48

10 values

Divide 433 by 10

433/10

43.3

The mean of the set of data is 43.3 and the correct answer is C.

43.3

Step-by-step explanation:

I added up all the numbers and divided by the number of numbers.

step-by-step explanation:

im not sure what the answer is

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.