assume the initial velocity is 60 feet/second. what is the maximum horizontal distance possible and at what angle does this occur

h = 112.5 feets

Step-by-step explanation:

The equation for horizontal distance "h" in feet of a projectile with initial velocity v₀ and initial angle theta is given by :

We know that,

So,

Now we need to find the maximum horizontal distance possible and at what angle does this occur.

For maximum distance angle should be 45 degrees. Som,

So, 112.5 feets is the maximum possible distance.

1,8,15,22,29,36,43,50

step-by-step explanation: