Please help me with this geometry question:((

a.ans=(1,3)

b.ans=(1,2,3,4,5,6,7,9,11,12)

c.ans=(1,3,5,7,9,11)

Step-by-step explanation:

Between A and C (1,3) are common.So it is the intersection.

(1,2,3,4,5,6,7,9,11,12) are all the number belongs to set A and set C.So it is called the union of both sets.

C denotes the complement and the number except set b belong to the complement.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

f(2x−x2)=−3x2+6x−1

step-by-step explanation:

set up the composite function and evaluate.

f(2x−x2)=−3x2+6x−1