Evaluate the polynomial when x = 3 and y = - 8
x2 + y2 + xy

Work Shown:

Replace x with 3, replace y with -8. Use order of operations PEMDAS to simplify.

x^2 + y^2 + x*y

3^2 + (-8)^2 + 3*(-8)

9 + 64 - 24

73 - 24

49

49

Step-by-step explanation:

We are given the polynomial:

We want to evaluate when x=3 and y= -8. Therefore, we must substitute 3 for each x and -8 for each y.

Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction

Solve the parentheses first. Multiply 3 and -9.

3*-8=-24

Now, solve the exponents.

3^2= 3*3 =9

-8^2= -8*-8= 64

Add 9 and 64

Subtract 24 from 73

The polynomial evaluated for x=3 and y= -8 is 49.

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.