Helen made a scale drawing of the middle school. The gym is 195 inches long in the drawing. The actual gym is 104 feet long. What scale did Helen use?

5 inches on the drawing = 32 actual inches

Step-by-step explanation:

195 inches

104 x 12 = 1248 inches

1/39

she used a scale of 5 inches to represent 32 inches actual length

Step-by-step explanation:

We are told that helen made the gym to be 195 inches long in the drawing.

Now, we are told that the actual length of the gym is 104 ft long.

Thus, converting to inches,

1ft = 12 inches

So, 104ft = 104 × 12 = 1248 inches

Which means that 194 inches represented 1248 inches.

So the scale is:

195:1248

Dividing both by a common factor of 39 to give a scale of (195/39):(1248/39)

This gives;

5:32

So she used a scale of 5 inches to represent 32 inches actual length

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°