Mathematics, 12.08.2020 04:01 kassidyopry15
A container in form of a frustum of a cone is 16 cm in diameter at the open end and 24 cm diameter at the bottom. If the vertical depth of the container is 8 cm calculate the capacity of the container.
Answers: 2
![\text{Volume}=\frac{\pi h}{3}\cdot[R^{2}+Rr+r^{2}]](/tpl/images/0718/0211/fd368.png)
![=\frac{\pi\cdot8}{3}\cdot[(12)^{2}+(12\cdot 8)+(8)^{2}]\\\\=\frac{8\pi}{3}\times [144+96+64]\\\\=\frac{8\pi}{3}\times304\\\\=2546.784445\\\\\approx 2546.78](/tpl/images/0718/0211/0c097.png)
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A container in form of a frustum of a cone is 16 cm in diameter at the open end and 24 cm diameter a...
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