The sides of two cubes are in ratio of 1:3. What is the ratio of the areas of these cubes ? What is the ratio of their volume ?

The ratio of their surface areas would 1:9 and the ratio of their volumes would be 1:27

Step-by-step explanation:

Given Info: The sides of two cubes are in ratio of 1:3. We can assign one square x and the other square 3x.

We know that the area of a square is its side squared, and that a cube has 6 sides. So thus if we assign one side of the cube x we can assume that surface area is 6x^2:

Surface Area of Cube #1= 6x^2

Surface Area of Cube #2= 6((3x)^2) = 6(9x^2) = 54x^2

Ratio of Surface Area: 6x^2 : 54x^2 = 6:54 = 1:9

Now for the volume we know that it is equivalent to one side cubed. So after assigning x to one cube, we can assume that volume would be x^3.

Volume of Cube #1= x^3

Volume of Cube #2= (3x)^3 = 27x^3

Ratio of Volume: x^3: 27x^3 = 1:27

Hope this helps!

answer: it's upside down and i can't read it

step-by-step explanation:

126 maybe. sorry