TAYLOR POLYNOMIALS AND ERROR IN TAYLOK SERIES Let f(x) = x4 + x3 + x2 + x + 1
(a) Use Taylor's Theorem to compute the remainder R 3 ( x ) in terms of value c that lies between 0 and x.
(b) Give an upper bound on the error assuming x∈ [ − 4 , 4 ].
(c) Compute the exact value of c (in terms of x) so that R 3 ( x ) = f ( x ) − p 3 ( x ) and R 3 ( x ) in part (a) agree.
Note: p 3 ( x ) is the 3rd-order Taylor polynomial.

the formula of a slope:

from a table we have

substitute:

the slope of f(x) is -1.

the graph of funcfion g(x) is a horizontal line. the slope of a horizontal line is equal 0. therefore the slope of g(x) is 0.

-1 < 0

2x^2+5x+17

your welcome. : )

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step-by-step explanation:

ever thing time 1 is a multiply by 1 it get  

step-by-step explanation:

for exempl this   system of equations   y = x - 3

                                                                y = 2x - 5

look   the line : y = x -3     ( red)

                            the line : y = 2x -5 ( bleus)