The amount of air present in a cylinder when a vacuum pump removes1/4 air remaining in the cylinder at a time. is this an ap?

It is not an ap

Step-by-step explanation:

Step-by-step explanation:

Let a be the amount of air initially Amount of air remaining after 1st pump =a –(a/4)=3a/4

Amount of air remaining after 2nd  pump= (3a/4) – (1/4)(3a/4)=9a/16

Amount of air remaining after 3rd  pump= (9a/16) – (1/4)(9a/16)=27a/64

So the series is like

a,3a/4,9a/4,27a/64……..

Difference Ist and second term=-a/4

Difference between Second and Third term= -3a/16

So difference is not constant

So it is not Arithmetic Progression

It is not an ap

Step-by-step explanation:

Step-by-step explanation:

Let a be the amount of air initially Amount of air remaining after 1st pump =a –(a/4)=3a/4

Amount of air remaining after 2nd  pump= (3a/4) – (1/4)(3a/4)=9a/16

Amount of air remaining after 3rd  pump= (9a/16) – (1/4)(9a/16)=27a/64

So the series is like

a,3a/4,9a/4,27a/64……..

Difference Ist and second term=-a/4

Difference between Second and Third term= -3a/16

So difference is not constant

So it is not Arithmetic Progression

answer: i don't understand. what are the options

step-by-step explanation:

not only in mathematics, scientific proof also are required in the other field of science. also maths proofs are of particular structure, containing steps and logics. so proving is like doing science, it is science. that's why it is important to prove. 

an inaccurate proof leads to errors, or stating results that are not accurate.  which wil mess the probelm up you dont want this