1. If one zero of the quadratic polynomial kx² + 3x + k is 2 then the value of k is *

Step-by-step explanation:

Given one zero of the quadratic polynomial kx² + 3x + k is 2,

Substitute x = 2 in the polyomial , we get

k(2)²+3×2+k = 0

=> 4k + 6 + k = 0

5k+6 = 0

5k= -6

k= -6/5

Therefore,

Value of k = -6/5

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

me! what did you put for this question?

step-by-step explanation: