A 10 gram sample of a substance that’s used to detect explosives has a k-value of 0.1356.Find the substances half life in days. Round your answer to the nearest tenth.

t ≈ 5.1 days

Step-by-step explanation:

A 10 gram sample of a substance thats used to detect explosives has a k-value of 0.1356. Find the substances half-life in days. round your answer to the nearest tenth. N=N₀ e^-kt N₀= initial mass (at time t = 0) N = mass at time t k= a positive constant that depends on the substance itself and on the units used to measure time t=time in days

The initial condition is that, at time t = 0, the amount of substance contains originally 10 grams

Find the value of N₀

N=N₀ e^-kt

We substitute:

10 = N₀ {e^(-0.1356)*0}

10 = N₀ (e^0)

10=N₀(1)

10=N₀

N₀ = 10

When the substance is in half-life

That is, half of the original substance (5 grams)

Find t

N=N₀ e^-kt

5 = 10 e^(-0.1356*t)

0.5 = e^(-0.1356*t)

Bring down t by multiplying natural log on both sides

ln(0.5) = -0.1356*t

Divide both sides by -0.1356

t = -(ln(0.5) / 0.1356

t ≈ 5.11 days

To the nearest tenth

t ≈ 5.1 days

there are no short passages to look at

deez nu tz

step-by-step explanation: