If 3sinA+4cosA=5 then find the value of cosA

cos(A) = 4/5

Step-by-step explanation:

3sinA+4cosA=5

Divide by 5 on both sides

(3/5)sinA+(4/5)cosA = 1 (1)

from which sin(A) = 3/5, cos(A) = 4/5  by inspection, since

(3/5)^2+(4/5)^2 = 1

For more details,

Let

cos(B) = (3/5), then

sin(B) = (4/5)

Substitute in (1)

cos(B)sin(A) + sin(B)cos(A) = 1          substitute trigonometric sum

sin(A+B) = 1  => A & B are complementary

cos(A) = sin(B) = 4/5

step-by-step explanation: i dont